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Example:
Let's find size of the segment (E) of the thin cross hair at
100 m distance with 8 x magnification.
The specified step at 100 m distance and 12x
magnification is10cm.
Now we shall calculate its size at 8x magnification:
E = (10 х 12): 8 = 15 cm at 100 m.
The distance to the target also influences the
corresponding sizes of the reticle.
Size of the segment = (calculated size of reticle @100m)
х K,
where K- adjustment for particular distance and equals
to:
= 0.5 – for 50 m distance,
= 1.0 – for 100 m distance,
= 2.0 – for 200 m distance,
= 3.0 – for 300 m distance (etc).
Example:
Let's find size of the segment (E) of the thin cross hair at
300 m distance with 8 x magnification.
The specified step at 100 m distance and 8x magnification
is15cm. At 300m it is equal to:
E=15x(300:100) = 45 cm